A) 4
B) 3
C) 1
D) 0
E) 2
Correct Answer: E
Solution :
The given equation is\[|x|={{x}^{2}}+x-4\] If \[x\ge 0,x={{x}^{2}}+x-4\] \[\Rightarrow \]\[{{x}^{2}}-4=0\Rightarrow x=\pm 2\] \[\therefore \]We take,\[x=2\](neglect\[x=-2\]) and if\[x<0\] \[-x={{x}^{2}}-x-4\] \[\Rightarrow \] \[{{x}^{2}}=4\Rightarrow x=\pm 2\] \[\therefore \]We take\[x=-2\](neglect\[x=2\]) Thus, the number of roots of given equation is 2.You need to login to perform this action.
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