A) 5 unit
B) 6 unit
C) 8 unit
D) 9 unit
E) 10 unit
Correct Answer: E
Solution :
Perpendicular distance of the point (6, 5, 8) from y-axis\[=\sqrt{{{6}^{2}}+{{8}^{2}}}=\sqrt{36+64}=\sqrt{100}\] =10 unit
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