A) 0
B) 1
C) 2
D) 3
E) 4
Correct Answer: D
Solution :
Given that, \[\frac{x+2}{{{x}^{2}}+1}>\frac{1}{2}\] \[\Rightarrow \] \[2x+4>{{x}^{2}}+1\] \[\Rightarrow \] \[{{x}^{2}}-2x-3<0\] \[\Rightarrow \] \[(x-3)(x+1)<0\] \[\Rightarrow \] \[-1<x<3\] The value of x are 0, 1, 2. \[\therefore \]The number of integral solutions is 3.You need to login to perform this action.
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