A) 200m
B) 125m
C) 160m
D) 190m
E) 300m
Correct Answer: A
Solution :
The given equation is \[x=100t-\frac{25}{2}{{t}^{2}}\] On differentiating w.r.t.\[x,\]we get \[\frac{dx}{dt}=100-\frac{25}{2}.(2t)=100-25t\] We know that the velocity of missile is zero at maximum height. \[\therefore \]On putting\[\frac{dx}{dt}=0,\]we get \[100-25t=0\] \[\Rightarrow \] \[t=4\] \[\therefore \]\[x=100\times 4-\frac{25\times 16}{2}=400-200\] \[=200m\]You need to login to perform this action.
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