A) 0.5 A
B) 15 A
C) 5 A
D) 1.5 A
E) 2.5 A
Correct Answer: C
Solution :
Magnetic force on the rod \[=BIl\] Weight of the rod\[=mg\] For no tension in wire, \[BIl=mg\] Or \[I=\frac{mg}{Bl}=\frac{1\times 10}{2\times 1}=5A\]You need to login to perform this action.
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