A) \[0.50\text{ }T\]
B) \[0.02\text{ }T\]
C) \[{{10}^{-3}}T\]
D) \[0.1\text{ }T\]
E) \[0.01\text{ }T\]
Correct Answer: E
Solution :
\[e=200\,\sin \,100\pi t\] We have, \[{{e}_{0}}=200,\] \[\omega =100\,\pi \] \[\because \] \[BAN\omega ={{e}_{0}}\] \[\therefore \] \[B=\frac{{{e}_{0}}}{AN\omega }\] \[=\frac{200}{(0.25\times 0.25)\times 1000\times 100\pi }\] Or \[B=0.01\,T\]You need to login to perform this action.
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