A) \[6.5\times {{10}^{-4}}mm\]
B) \[1.3\,\,micron\]
C) \[3250\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[2.6\times {{10}^{-4}}cm\]
E) \[1.3\times {{10}^{-4}}m\]
Correct Answer: B
Solution :
According to principle of diffraction \[a\sin \theta =n\lambda \] where\[n=\]order of secondary minimum \[\therefore \] \[a\sin 30{}^\circ =1\times (6500\times {{10}^{-10}})\] or \[a=1.3\times {{10}^{-6}}m\] or \[a=1.3\text{ }micron\]
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