A) 50%
B) 75%
C) 100%
D) 60%
E) 25%
Correct Answer: B
Solution :
\[\frac{N}{{{N}_{0}}}={{\left( \frac{1}{2} \right)}^{t/T}}={{\left( \frac{1}{2} \right)}^{\frac{10}{5}}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}=25%\] This is probability of remaining portion of radium. So, probability of decay \[=(100-25)%=75%\]
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