A) 0:073 eV
B) 1:2 eV
C) 7.3 eV
D) 1.16 eV
E) 0.73eV
Correct Answer: E
Solution :
Energy\[=\frac{hc}{\lambda }\] \[=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1700\times {{10}^{-9}}\times 1.6\times {{10}^{-19}}}eV\] \[=0.73\,eV\]
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