question_answer

A mass of 6 kg is suspended by a rope of length 2 m from a ceiling. A force of 50 N in the horizontal direction is applied at the mid-point of the rope. The angle made by the rope with the vertical, in equilibrium is

A)  \[50{}^\circ \]                                  

B)  \[60{}^\circ \]                  

C)  \[30{}^\circ \]                  

D)         \[40{}^\circ \]

E)  \[5.5{}^\circ \]

Correct Answer: D

Solution :

\[\tan \theta =\frac{50}{6g}=0.83\] or     \[tan\text{ }\theta =tan\text{ }40{}^\circ \] or        \[\theta =40{}^\circ \]