CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    The work done in moving an alpha particle between two points having potential difference 25 V is

    A)  \[8\times {{10}^{-18}}J\]             

    B)         \[8\times {{10}^{-19}}J\]

    C)  \[8\times {{10}^{-20}}J\]             

    D)         \[8\times {{10}^{-16}}J\]

    E)  \[4\times {{10}^{-18}}J\]

    Correct Answer: A

    Solution :

    Required work done, \[W=QV\] \[=(2e)\times 25\] \[=50\,e=50\times 1.6\times {{10}^{-19}}\] \[=8\times {{10}^{-18}}J\]


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