CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2007

  • question_answer
    Identify the product/s in the following reaction. \[3C{{H}_{3}}CH=C{{H}_{2}}\xrightarrow[{}]{B{{H}_{3}}}X\xrightarrow[{}]{{{H}_{2}}{{O}_{2}}/O{{H}^{-}}}\] \[product/s+{{H}_{3}}B{{O}_{3}}\]

    A)  \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]

    B)  \[C{{H}_{3}}CHOHC{{H}_{3}}\]

    C)  \[C{{H}_{3}}C{{H}_{2}}CHO\]

    D)  \[C{{H}_{3}}C{{H}_{2}}OH+C{{H}_{3}}OH\]

    E)  \[C{{H}_{3}}CHO+C{{H}_{3}}OH\]

    Correct Answer: A

    Solution :

    \[3C{{H}_{3}}CH\equiv C{{H}_{2}}\xrightarrow[{}]{+B{{H}_{3}}}\] \[{{(C{{H}_{3}}C{{H}_{2}}-C{{H}_{2}}-)}_{3}}B\xrightarrow[{}]{{{H}_{2}}{{O}_{2}}/O{{H}^{-}}}\]                                 \[3C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH+{{H}_{3}}B{{O}_{3}}\]


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