A) \[11:10\]
B) \[81:19\]
C) \[10:11\]
D) \[15:16\]
E) \[19:81\]
Correct Answer: E
Solution :
Let abundance of\[{{B}^{10}}\]be m% . So, abundance of \[{{B}^{11}}=(100-m)%\] \[\therefore \] \[10.81=\frac{(10\times m)+11(100-m)}{100}\] Or \[1081=10m+1100-11m\] Or \[m=19\] \[\therefore \] Ratio of abundances \[=\frac{19}{100-19}=\frac{19}{81}\]You need to login to perform this action.
You will be redirected in
3 sec