A) 60%
B) 40%
C) 20%
D) 30%
E) 50%
Correct Answer: D
Solution :
Work done in raising water \[=mgh\] or \[W=(volume\times density)gh\] \[=(9\times 1000)\times 10\times 10\] or \[W=9\times {{10}^{5}}J\] \[\therefore \]Useful power \[=\frac{work}{t}=\frac{9\times {{10}^{5}}}{5\times 60}=3\,kW\] Hence, \[efficiency=\frac{useful\text{ }power}{consuming\text{ }power}\] \[=\frac{3}{10}=30%\]You need to login to perform this action.
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