A) \[20\text{ }m{{s}^{-1}}\]
B) \[10\text{ }m{{s}^{-1}}\]
C) \[75\text{ }m{{s}^{-1}}\]
D) \[26\text{ }m{{s}^{-1}}\]
E) \[50\text{ }m{{s}^{-1}}\]
Correct Answer: E
Solution :
Area under the F-t curve = change in momentum Or \[\frac{1}{2}\times 2\times (10)+2\times 10+\frac{1}{2}(10+20)\times 2\] \[+\frac{1}{4}\times 4\times 20=m(v-u)\] Or \[10+20+30+40=2(v-0)\] Or \[100=2v\] Or \[v=50\,m{{s}^{-1}}\]You need to login to perform this action.
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