A) \[G/2\]
B) \[G\]
C) \[2G\]
D) \[4G\]
E) \[8G\]
Correct Answer: C
Solution :
Gravitational potential \[V=GM\left( \frac{1}{{{r}_{1}}}+\frac{1}{{{r}_{2}}}+\frac{1}{{{r}_{3}}}+...... \right)\] \[=G\times 1\left( \frac{1}{1}+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+.... \right)\] \[=G\left( \frac{1}{1-1/2} \right)\] \[\left( \because sum\,of\,GP=\frac{a}{1-r} \right)\]You need to login to perform this action.
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