A) 13.6m
B) 40.8m
C) 27.2m
D) 54.4m
E) 6.8m
Correct Answer: B
Solution :
The depression of level in the left limb is 1 cm, so the rise of level of mercury in right limb be 2 cm, because the area of cross-section of left limb is twice as that of right limb. Now, equating pressure at interface of mercury and water (at AB) \[(x+1)\times {{10}^{3}}\times g=(1+2)\times 13.6\times {{10}^{3}}g\] or height of water column \[x+1=40.8\text{ }m\]You need to login to perform this action.
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