question_answer

Of the isomeric hexanes, the isomers that give the minimum and maximum number of monochloro derivatives are respectively

A) 3-methylpentane and 2,3-dimethylbutane

B) 2, 3-dimethylbutane and n-hexane

C) 2, 2-dimethylbutane and 2-methylpentane

D) 2, 3-dimethylbutane and 2-methylpentane

E) (d) 2-methylpentane and 2, 2-dimethylbutane

Correct Answer: D

Solution :

The possible isomers of hexane are (i)              (ii) (iii)          (iv) Out of these structure (iii) and (i) have respectively minimum and maximum number of monochloroderivatives For structure (iii), (a)                     (b) [Only 2 monochloroderivatives (minimum) are possible] For structure (i), (a)        (b) (c)              (d)    [5 monochloroderivatives (maximum) are possible]