A) 2
B) \[-2\]
C) 3
D) \[-3\]
E) \[-5\]
Correct Answer: D
Solution :
Since, \[A=\left[ \begin{matrix} {{\alpha }^{2}} & 5 \\ 5 & -\alpha \\ \end{matrix} \right]\] Now, \[|A|=-{{a}^{3}}-25\] Also, \[|{{A}^{10}}|=1024\] \[\Rightarrow \] \[|{{A}^{10}}|={{2}^{10}}\] \[\Rightarrow \] \[{{(-{{\alpha }^{3}}-25)}^{10}}={{2}^{10}}\] \[\Rightarrow \] \[-{{\alpha }^{3}}-25=2\] \[\Rightarrow \] \[-{{\alpha }^{3}}=27\] \[\Rightarrow \] \[\alpha =-3\]You need to login to perform this action.
You will be redirected in
3 sec