A) 2
B) \[-2\]
C) 1
D) \[-1\]
E) 0
Correct Answer: B
Solution :
\[\underset{x\to -\infty }{\mathop{\lim }}\,=\frac{2x-1}{\sqrt{{{x}^{2}}+2x+1}}=\underset{y\to \infty }{\mathop{\lim }}\,\frac{-2-\frac{1}{y}}{\sqrt{1-\frac{2}{y}+\frac{1}{{{y}^{2}}}}}\] \[(Putx=-y\therefore x\to -\infty \,ie,y\to \infty )\] \[=-\frac{1}{2}=-2\]You need to login to perform this action.
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