A) \[5\]
B) \[0\]
C) \[\frac{2}{\sqrt{1+{{x}^{2}}}}\]
D) \[\frac{2}{\sqrt{1-{{x}^{2}}}}\]
E) \[\frac{2}{\sqrt{1-{{x}^{2}}}}\]
Correct Answer: B
Solution :
Given, \[y={{\sin }^{-1}}{{(3x-4x)}^{2}}+{{\cos }^{-1}}(4{{x}^{3}}-3x)\] \[+{{\tan }^{-1}}(E)\] \[\Rightarrow \]\[y=3{{\sin }^{-1}}x+3{{\cos }^{-1}}x+{{\tan }^{-1}}(E)\] \[\Rightarrow \] \[y=\frac{3\pi }{2}+{{\tan }^{-1}}(E)\] On differentiating w.r.t.\[x,\]we get \[\frac{dy}{dx}=0\]You need to login to perform this action.
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