CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    If\[{{x}^{2}}+2x+n>10\]for all real number\[x,\]then which of the following conditions is true?

    A)  \[n<11\]                             

    B)  \[n=10\]

    C)  \[n=11\]             

    D)         \[n>11\]

    E)  \[n<-11\]

    Correct Answer: D

    Solution :

    Given inequality can be rewritten as \[{{x}^{2}}+2x+n-10>0\]                     ...(i) As we know, if\[ax+bx+c>0,\]then\[a>0\]and\[D<0\]. \[\therefore \]From Eq. (i),\[D<0\] \[\Rightarrow \]               \[{{(2)}^{2}}-4(n-10)<0\] \[\Rightarrow \]               \[4-4(n-10)<0\] \[\Rightarrow \]               \[n-10>1\] \[\Rightarrow \]               \[n>11\]


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