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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    The coefficient of x in the expansion of\[(14+x)(1+2x)(1+3x)....(1+100x)\]is

    A)  5050                                     

    B)  10100

    C)  5151                     

    D)         4950

    E)  1100

    Correct Answer: A

    Solution :

    The coefficient of\[x\]in the expansion of \[(1+x)(1+2x)(1+3x)....(1+100x)\]\[=1+2+3+....+100\] \[=\frac{100(100+1)}{2}=50\times 101=5050\]


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