CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    If the expansion of\[{{\left( \frac{3\sqrt{x}}{7}-\frac{5}{2x\sqrt{x}} \right)}^{13n}}\]contains  a term independent of\[x\]in the 14th term, then n should be

    A)  10                                         

    B)  5

    C)  6                            

    D)         4

    E)  11

    Correct Answer: D

    Solution :

    The 14th term in the expansion of \[\left( \frac{3\sqrt{x}}{7}-\frac{5}{2x\sqrt{x}} \right)\]is \[{{T}_{14}}{{=}^{13n}}{{C}_{13}}{{\left( \frac{3}{7}{{x}^{1/2}} \right)}^{13n-13}}{{(-1)}^{13}}{{\left( \frac{5}{2}{{x}^{-3/2}} \right)}^{13}}\] \[{{=}^{13n}}{{C}_{13}}{{\left( \frac{3}{7} \right)}^{13n-13}}{{(-1)}^{13}}{{\left( \frac{5}{2} \right)}^{13}}{{x}^{\frac{13n-13}{2}-\frac{39}{2}}}\] For this term to be independent of\[x,\]we put \[13n-52=0\] \[\Rightarrow \]               \[n=4\]


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