CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    The set of admissible values of\[x\]such that\[\frac{2x+3}{2x-9}<0\]is

    A)  \[\left( -\infty ,-\frac{3}{2} \right)\cup \left( \frac{9}{2},\infty  \right)\]

    B)  \[(-\infty ,0)\cup \left( \frac{9}{2},\infty  \right)\]

    C)  \[\left( -\frac{3}{2},0 \right)\]

    D)  \[\left( 0,\frac{9}{2} \right)\]

    E)  \[\left( -\frac{3}{2},\frac{9}{2} \right)\]

    Correct Answer: E

    Solution :

    Given, \[\frac{2x+3}{2x-9}<0\] \[\Rightarrow \]\[2x+3<0\]and\[2y-9>0\] or\[2x+3>0\]and\[2x-9<0\]and\[x\ne \frac{9}{2}\] \[\Rightarrow \]\[x<-\frac{3}{2}\]and\[x>\frac{9}{2}\]or\[x>-\frac{3}{2}\]and\[x<\frac{9}{2}\]and\[x\ne \frac{9}{2}\] \[\Rightarrow \]\[\left( -\frac{3}{2},\frac{9}{2} \right)\]


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