A) \[\frac{\sqrt{3}+1}{3\sqrt{3}}cm\]
B) \[\frac{60}{13}cm\]
C) \[\frac{65}{12}cm\]
D) \[\frac{144}{13}cm\]
E) \[\frac{65}{13}cm\]
Correct Answer: B
Solution :
Since, \[a=13\text{ }cm,\text{ }b=12\text{ }cm,\text{ }c=5\text{ }cm\] Now, \[{{(13)}^{2}}={{(5)}^{2}}+{{(12)}^{2}}\] \[\Rightarrow \] \[169=169\] So,\[\Delta ABC\]is a right angled triangle. \[\therefore \] Area \[=\frac{1}{2}\times 5\times 12=30\,c{{m}^{2}}\] Again, area \[=\frac{1}{2}\times BC\times AD\] \[\Rightarrow \] \[30=\frac{1}{2}\times 13\times AD\] \[\Rightarrow \] \[AD=\frac{60}{13}cm\]You need to login to perform this action.
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