A) (0, 1) is \[0\]
B) \[1\,sq\,unit\]
C) \[\frac{1}{2}\,sq\,unit\]
D) \[2\,sq\,unit\]
E) \[4\,sq\,unit\]
Correct Answer: B
Solution :
Given curve is\[y={{e}^{2x}}+{{x}^{2}}\] \[\therefore \] \[\frac{dy}{dx}=2{{e}^{2x}}+2x\] \[\Rightarrow \] \[{{\left( \frac{dy}{dx} \right)}_{(0,1)}}=2\] \[\therefore \]Equation of normal is \[y-1=-\frac{1}{2}(x-0)\] \[\Rightarrow \] \[y+\frac{x}{2}=1\] \[\therefore \]Area of \[\Delta OAB=\frac{1}{2}\times 2\times 1\] \[=1\text{ }sq\text{ }unit\]You need to login to perform this action.
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