A) \[(-3,0)\cup (3,\infty )\]
B) \[(-\infty ,-3)\cup (3,\infty )\]
C) \[(-\infty ,-3)\cup (0,3)\]
D) \[(-3,3)\]
E) \[(3,\infty )\]
Correct Answer: A
Solution :
Given, \[f(x)={{(9-{{x}^{2}})}^{2}}\] On differentiating w.r.t.\[x,\]we get \[f(x)=2(9-{{x}^{2}})(-2x)\] Now, put \[f(x)=0\] \[\Rightarrow \] \[2(9-{{x}^{2}})(-2x)=0\] \[\Rightarrow \] \[x=0,\pm 3\] \[\therefore \]\[f(x)\]is increasing in\[(-3,0)\cup (3,\infty )\].You need to login to perform this action.
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