A) 1
B) 2
C) 3
D) 4
E) 5
Correct Answer: D
Solution :
Let\[I=\int_{-2}^{2}{|[x]|}dx\] \[=\int_{-2}^{-1}{|[x]|}\,dx+\int_{-1}^{0}{|[x]}|\,dx+\int_{0}^{1}{|[x]|dx}\] \[+\int_{1}^{2}{|[x]}|dx\] \[=\int_{-2}^{-1}{2dx}+\int_{-1}^{0}{1\,dx}+\int_{0}^{1}{0}dx+\int_{1}^{2}{1\,dx}\] \[=2[x]_{-2}^{-1}+[x]_{-1}^{0}+0+[x]_{1}^{2}\] \[=2(-1+2)+(0+1)+(2-1)\] \[=2+1+1=4\]You need to login to perform this action.
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