A) 2512 kHz and 2508 kHz
B) 2522 kHz and 2488 kHz
C) 2502 kHz and 2498 kHz
D) 2522 kHz and 2498 kHz
E) 2512 kHz and 2488 kHz
Correct Answer: D
Solution :
Upper side band (USB) frequency \[={{f}_{c}}+{{f}_{m}}\] \[=(2.51)\text{ }MHz+(12)\text{ }kHz\] \[=(2510+12)\text{ }kHz\] \[=2522\text{ }kHz\] Lower side band (LSB) frequency\[={{f}_{c}}-{{f}_{m}}\] \[=(2.51)\text{ }MHz-(12)\text{ }kHz\] \[=(2510-12)\text{ }kHz\] \[=2498\text{ }kHz\]
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