A) \[{{45}^{o}}C\]
B) \[{{90}^{o}}C\]
C) \[{{30}^{o}}C\]
D) \[{{20}^{o}}C\]
E) \[{{60}^{o}}C\]
Correct Answer: E
Solution :
Let the temperature of junction be\[\theta ,\]then \[H={{H}_{1}}+{{H}_{2}}\] \[\Rightarrow \] \[\frac{KA(\theta -0)}{L}=\frac{KA(90-\theta )}{L}+\frac{KA(90-\theta )}{L}\] or \[\theta =90-\theta +90-\theta \] or \[\theta =180-26\] or \[3\theta =180\] or \[\theta =60{}^\circ C\]You need to login to perform this action.
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