A) zero
B) \[\pi /3\]
C) \[\pi /2\]
D) \[\pi /6\]
E) \[\pi /4\]
Correct Answer: B
Solution :
Given that \[{{B}_{H}}=\frac{1}{\sqrt{3}}{{B}_{V}}\] Also, \[\tan \theta =\frac{{{B}_{V}}}{{{B}_{H}}}=\sqrt{3}=\tan {{60}^{o}}\] \[\therefore \] \[\theta =60{}^\circ =\frac{\pi }{3}\]You need to login to perform this action.
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