A) \[\left( \frac{2}{5},\frac{2}{5} \right)\]
B) \[\left( \frac{3}{5},\frac{3}{5} \right)\]
C) \[\left( \frac{1}{5},\frac{1}{5} \right)\]
D) \[\left( \frac{3}{5},\frac{2}{5} \right)\]
E) \[\left( \frac{2}{5},\frac{3}{5} \right)\]
Correct Answer: E
Solution :
Given equation is \[(a+2b)\text{ }x+(a-3b)\text{ }y=a-b\] It can be rewritten as \[a(x+y-1)+b(2x-3y+1)=0\] This is the form of intersection of two lines. \[\therefore \] \[x+y-1=0\] and \[2x-3y+1=0\] On solving, we get \[x=\frac{2}{5}\]and\[y=\frac{3}{5}\]You need to login to perform this action.
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