A) 1 g
B) 2 g
C) 3 g
D) 5 g
E) 2.5 g
Correct Answer: D
Solution :
Freundlich adsorption isotherm equation is \[\frac{x}{m}=k{{p}^{1/n}}\] On taking log both sides \[\log \frac{x}{m}=\log k+\frac{1}{n}\log \,p\] \[\log \frac{x}{m}=\log \,10+\frac{1}{n}\log \,0.5\] (\[\because \]\[slope=\frac{1}{n}=tan\,\theta =tan\text{ }45{}^\circ =1\]) \[\log \frac{x}{m}=1+\frac{1}{1}\log (5\times {{10}^{-1}})\] \[\log \frac{x}{m}=1-0.6990+1\] \[=0.6990\] \[\frac{x}{m}=5.00\] \[=5g.\]You need to login to perform this action.
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