A) 5/16
B) 9/40
C) 9/41
D) 19/41
E) None of these
Correct Answer: C
Solution :
Now, \[O{{B}^{2}}=O{{A}^{2}}+A{{B}^{2}}\] \[={{40}^{2}}+{{9}^{2}}=1681\] \[\Rightarrow \] \[OB=41\] \[\therefore \] \[sin\angle AOB=\frac{AB}{OB}=\frac{9}{41}\]You need to login to perform this action.
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