question_answer

If A and B are any two events, then\[P(A\cap B)\]is equal to

A)  \[P(A)+P(B)\]

B)         \[P(A)P(B)\]

C)  \[P(B)-P(A\cap B)\]

D)         \[P(A)-P(A\cap B)\]

E)  \[1-P(A\cap B)\]

Correct Answer: D

Solution :

\[\therefore \] \[p(A\cap B)=p(A)-p(A\cap B)\]