A) \[a\cos e{{c}^{3}}x\]
B) \[a\cot {{x}^{2}}-4{{x}^{2}}\cos e{{c}^{2}}{{x}^{2}}\]
C) \[2x\cot {{x}^{2}}\]
D) \[-2\cos e{{c}^{2}}x\]
E) \[4\cos e{{c}^{2}}x\]
Correct Answer: D
Solution :
Given, \[f(x)=\sin x,g(x)={{x}^{2}}\] and \[h(x)={{\log }_{e}}x\] Also, \[f(x)=(hogof)(x)\] Now, \[[hog](x)=2{{\log }_{e}}x\] \[\Rightarrow \] \[(hogof)(x)=2{{\log }_{e}}x\] \[\Rightarrow \] \[f(x)=2{{\log }_{e}}\sin x\] On differentiating w.r.t.\[x,\]we get \[f(x)=2\cot x\] Again differentiating, we get \[f(x)=-2\cos e{{c}^{2}}x\]
You need to login to perform this action.
You will be redirected in
3 sec
