A) (0, 1) is \[0\]
B) \[1\,sq\,unit\]
C) \[\frac{1}{2}\,sq\,unit\]
D) \[2\,sq\,unit\]
E) \[4\,sq\,unit\]
Correct Answer: B
Solution :
Given curve is\[y={{e}^{2x}}+{{x}^{2}}\] \[\therefore \] \[\frac{dy}{dx}=2{{e}^{2x}}+2x\] \[\Rightarrow \] \[{{\left( \frac{dy}{dx} \right)}_{(0,1)}}=2\] \[\therefore \]Equation of normal isYou need to login to perform this action.
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