CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    Gas is being pumped into a spherical balloon at the rate of\[30\text{ }f{{t}^{3}}/min\]. Then, the rate at which the radius increases when it reaches the value 15ft is

    A)  \[\frac{1}{15\pi }ft/\min \]         

    B)  \[\frac{1}{30\pi }ft/\min \]

    C)  \[\frac{1}{20}ft/\min \]

    D)         \[\frac{1}{25}ft/\min \]

    E)  None of these

    Correct Answer: B

    Solution :

    Given,\[\frac{dV}{dt}=30f{{t}^{3}}/\min \]and\[r=15\text{ }ft\] Volume of spherical balloon                 \[V=\frac{4}{3}\pi {{r}^{3}}\] \[\Rightarrow \]               \[\frac{dV}{dt}=4\pi {{r}^{2}}\frac{dr}{dt}\] \[\Rightarrow \]               \[30=4\pi {{r}^{2}}\frac{dr}{dt}\] \[\Rightarrow \]               \[\frac{dr}{dt}=\frac{30}{4\times \pi \times 15\times 15}\]                                 \[=\frac{1}{30\pi }ft/\min \]


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