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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A particle starts from rest at\[t=0\]and moves in a straight line with an acceleration as shown in figure. The velocity of the particle at \[t=3\text{ }s\] is

    A)  \[2m{{s}^{-1}}\]              

    B)         \[4m{{s}^{-1}}\]              

    C)         \[6m{{s}^{-1}}\]              

    D)         \[8\,m{{s}^{-1}}\]

    E)  \[1\text{ }m{{s}^{-1}}\]

    Correct Answer: B

    Solution :

    Velocity at\[3s=\]total algebraic sum of area under the curve or          \[v=4\times 2-4\times 1\] \[=8-4=4m{{s}^{-1}}\]


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