A) \[1,-1\]
B) \[-1,1\]
C) \[1,1\]
D) \[-1,-1\]
E) \[1,0\]
Correct Answer: B
Solution :
Since,\[\int_{a}^{b}{{{x}^{3}}}dx=0\]and \[\int_{a}^{b}{{{x}^{2}}}dx=\frac{2}{3}\] \[\therefore \] \[\left[ \frac{{{x}^{4}}}{4} \right]_{a}^{b}=0\]amd \[\left[ \frac{{{x}^{3}}}{3} \right]_{a}^{b}=\frac{2}{3}\] \[\Rightarrow \] \[{{b}^{4}}-{{a}^{4}}=0\]and \[{{b}^{3}}-{{a}^{3}}=2\] \[\Rightarrow \] \[a=-1,b=1\]You need to login to perform this action.
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