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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A bullet of mass 0.05 kg moving with a speed of\[80\text{ }m{{s}^{-1}}\]enters a wooden block and is stopped after a distance of 0.40 m. The average resistive force exerted by the block on the bellow is

    A)  300 N                   

    B)         20 N                     

    C)  400 N                   

    D)         40 N

    E)  200 N

    Correct Answer: C

    Solution :

    Resistive force \[\frac{\text{initial}\,\text{kineticd}\,\text{energy}}{\text{stopping}\,\text{distance}}\] \[=\frac{\frac{1}{2}\times 0.05\times {{(80)}^{2}}}{0.40}=400\,N\]


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