CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A particle of mass 2 kg is initially at rest. A force acts on it whose magnitude changes with time. The force time graph is shown below. The velocity of the particle after 10 s is

    A)  \[20\text{ }m{{s}^{-1}}\]         

    B)         \[10\text{ }m{{s}^{-1}}\]             

    C)         \[75\text{ }m{{s}^{-1}}\]         

    D)         \[26\text{ }m{{s}^{-1}}\]

    E)  \[50\text{ }m{{s}^{-1}}\]

    Correct Answer: E

    Solution :

    Area under the F-t curve = change in momentum Or           \[\frac{1}{2}\times 2\times (10)+2\times 10+\frac{1}{2}(10+20)\times 2\]                 \[+\frac{1}{4}\times 4\times 20=m(v-u)\] Or           \[10+20+30+40=2(v-0)\] Or           \[100=2v\] Or           \[v=50\,m{{s}^{-1}}\]


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