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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    Three identical spheres, each of mass 3 kg are placed touching each other with their centres lying on a straight line. The centres of the sphere are marked at P, Q and R respectively. The distance of centre of mass of system from P is

    A)  \[\frac{PQ+QR+PR}{3}\]

    B)         \[\frac{PQ+PR}{3}\]      

    C)         \[\frac{PQ+QR+PR}{9}\]             

    D)  \[\frac{PQ+PR}{9}\]

    E)  \[\frac{PQ+QR}{3}\]

    Correct Answer: B

    Solution :

    \[{{X}_{CM}}=\frac{3\times 0+3\times PQ+3\times PR}{3+3+3}\] \[=\frac{3(PQ+PR)}{9}\] \[=\frac{PQ+PR}{3}\]


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