CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    If the volume of a block of aluminium is decreased by 1%, the pressure (stress) on its surface is increased by (Bulk modulus of \[Al=7.5\times {{10}^{10}}N{{m}^{-2}})\]

    A)  \[7.5\times {{10}^{10}}N{{m}^{-2}}\]  

    B)         \[7.5\times {{10}^{8}}\text{ }N{{m}^{-2}}\]

    C)         \[7.5\times {{10}^{6}}N{{m}^{-2}}\]  

    D)         \[7.5\times {{10}^{4}}N{{m}^{-2}}\]

    E)  \[7.5\times {{10}^{2}}N{{m}^{-2}}\]

    Correct Answer: B

    Solution :

    Given, \[\frac{\Delta V}{V}\times 100=1%=\frac{1}{100}\] Bulk modulus,                 \[B=\frac{p}{\Delta V/V}=\frac{pV}{\Delta V}\] Or           \[p=\frac{B\Delta V}{V}=7.5\times {{10}^{10}}\times \frac{1}{100}\]                 \[=7.5\times {{10}^{8}}N{{m}^{-2}}\]


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