A) 250 kHz
B) 25 kHz
C) 2.5 kHz
D) 25 MHz
E) 2.5MHz
Correct Answer: B
Solution :
In parallel resonant circuit resonance frequency \[{{f}_{o}}=\frac{1}{2\pi \sqrt{LC}}=\frac{1}{2\pi \sqrt{\frac{10\times {{10}^{-3}}}{{{\pi }^{2}}}\times 0.04\times {{10}^{-6}}}}\] \[=\frac{{{10}^{4}}}{2\times 0.2}=25\,kHz\]You need to login to perform this action.
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