A) \[\frac{q}{4}\]
B) \[\frac{2q}{\sqrt{32}}\]
C) \[\sqrt{2q}\]
D) \[+q\]
E) \[\frac{q}{\sqrt{2}}\]
Correct Answer: B
Solution :
Here total electrostatic potential energy is zero ie, \[\frac{-{{Q}_{0}}q}{l}-\frac{q{{Q}_{0}}}{l}+\frac{{{q}^{2}}}{\sqrt{2}l}=0\] On solving, \[{{Q}_{0}}=\frac{q}{2\sqrt{2}}=\frac{2q}{\sqrt{32}}\]You need to login to perform this action.
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