CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    The total energy of a simple harmonic oscillator is proportional to

    A)  square root of displacement

    B)  velocity

    C)  frequency

    D)  amplitude

    E)  square of the amplitude

    Correct Answer: E

    Solution :

    The energy of simple harmonic oscillator \[E=\frac{1}{2}m{{\omega }^{2}}{{A}^{2}}\] or            \[E\propto {{A}^{2}}\] ie, energy is proportional to square of the amplitude.


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