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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    A glass tube of length 1.0 m is completely filled with water. A vibrating tuning fork of frequency 500 Hz is kept over the mouth of the tube and the water is drained out slowly at the bottom of the tube. If velocity of sound in air is \[330\,m{{s}^{-1}},\] then the total number of resonances that occur will be

    A)  2                            

    B)         3                            

    C)  1                            

    D)         5

    E)  4

    Correct Answer: B

    Solution :

    \[f=\frac{v}{4l}\]or\[l=\frac{v}{4f}\] \[\therefore \]  \[{{l}_{1}}=\frac{v}{4{{f}_{1}}}=\frac{330}{4\times 500}=0.165\,m;\]                 \[{{l}_{2}}=\frac{3v}{4{{f}_{1}}}=3{{l}_{1}}=0.495;\]                 \[{{l}_{3}}=\frac{5v}{4{{f}_{1}}}=5{{l}_{1}}=0.825\,m\] And        \[{{l}_{4}}=\frac{7v}{4{{f}_{1}}}=7{{l}_{1}}=1.155>1\,m\] Therefore, number of resonance = 3.


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