CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2008

  • question_answer
    Small drops of the same size are charged to V volt each. If n such drops coalesce to form a single large drop, its potential will be

    A)  \[Vn\]                 

    B)         \[V/n\]

    C)  \[V{{n}^{1/3}}\]              

    D)         \[V{{n}^{2/3}}\]

    E)  \[V{{n}^{1/2}}\]

    Correct Answer: D

    Solution :

    \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}\] \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}=\frac{1}{4\pi {{\varepsilon }_{0}}}=\frac{nq}{{{n}^{1/3}}r}\]\[(\because q=nq,r={{n}^{1/3}}r)\] Or           \[V={{n}^{2/3}}V\]


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